![]() The code is on 2 seperate files below and the instructions are on an image doc below and within the code itself. I got most of it done I just need help with the last improvements and test case implementations. (Going through all 88,000 uppercase and lowercase words from the dictionary file may take a couple of minutes) Brute-Force PDF Password Breaker: Say you have an encrypted PDF file: encrypted.pd (Links to an external site.)f (Links to an external site.) that you have forgotten the password to, but you remember it was a single English word.Write a program that will decrypt the PDF by trying every possible English word until it finds one that works.Download the text file dictionary.txt (Links to an external site.), this dictionary file contains over 44,000 English words with one word per line.Using the file-reading skills you learned, create a list of word strings by reading this file.Then loop over each word in this list, passing it to the decrypt() method.If this method returns the integer 0, the password was wrong and your program should continue to the next password.If decrypt() returns 1, then your program should break out of the loop and print the hacked password.You should try both the uppercase and lowercase form of each word. Create a PDF from only those pages that have some specific text:Use the PDF: meetingminutes.pdf (Links to an external site.) to write a program that will create a PDF from only those pages that have the word: student2. Your paper must cite at least two technically credible sources in APA format.ġ. Guidelines for Submission: Your paper must be submitted as a two-page Microsoft Word document (not including title and references pages) with double spacing, 12-point Times New Roman font, and one -inch margins. Prompt: Write a short paper that recommends a deadlock avoidance approach most suitable for the TSI web server application that is not using an ordered acquisition of mutexes. Systems administrators are perplexed because the systems show all processes are active using the command except for the web server process, which appears to be waiting in a call to pthread_mutex_lock().Whentheyreboottheservers,theproblemdisappearsuntiltheserversgetbusyandthelock-upoccursagain.Thebusinessimpactof this problem is that TSI customers are unable to access the website to make purchases during peak periods. The result is that its web servers are periodically locking up. (TSI) finds that the TSI OS lacks mechanisms for the ordered acquisition of synchronization objects. ![]() If ‘n’ is the number of processes and ‘m’ is the number of resources.During the implementation of its new and improved back office operating system, Top Secret, Inc. The following are the various data structures that have to be created to implement Banker’s algorithm. If not, resources are allocated otherwise process has to wait. When the process requests resources, the system decides whether allocation will result in deadlock or not. It is obvious that this number should not be more than the available. Here, customers are analogous to processes, cash to resources, and bank to the operating system.Ī process must specify in the beginning the maximum number of instances of each resource type it may require. It is similar to a banking system where a bank never allocates cash in such a way that it could not satisfy the needs of all its customers and also it cannot allocate more than what is available. This is not possible, using the methods like safe state and resource allocation graphs. It is used to avoid deadlocks when multiple instances of each resource type are present. An edge from process P i to resource R j (P i → R j) indicates that P i has requested resource R j. ![]() The vertices are divided into two types, i.e., a set of processes, P =. It is a directed graph, given as G = (V, E) containing a set of vertices V and edges E. Thereafter, whenever a process requests, the algorithm must decide whether the allocation is safe or unsafe and accordingly the action should be taken. In the beginning, the system will be in a safe state, then processes are allocated to resources according to their current need. The above shows one of the safe sequences, there may be many safe sequences for the same example. P 3 is allocated its maximum requirements. P 1 is allocated its maximum requirements. ![]() P 2 is allocated its maximum requirements. The table below shows the sequence of resource allocation and release.Īt t 0 resources are allocated according to current needs. If the processes are executed in the sequence then the safety condition can be satisfied.
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